-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy pathprob6.py
More file actions
176 lines (164 loc) · 8.09 KB
/
Copy pathprob6.py
File metadata and controls
176 lines (164 loc) · 8.09 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
#!/usr/bin/env python
# Written against python 3.3.1
# Matasano Problem 6
# Break repeating-key XOR
# The buffer at the following location:
# https://gist.github.com/3132752
# is base64-encoded repeating-key XOR. Break it.
# Here's how:
#
# a. Let KEYSIZE be the guessed length of the key; try values from 2 to (say) 40.
#
# b. Write a function to compute the edit distance/Hamming
# distance between two strings. The Hamming distance is just the number of
# differing bits. The distance between:
#
# this is a test
# and:
# wokka wokka!!!
# is 37.
#
# c. For each KEYSIZE, take the FIRST KEYSIZE worth of bytes, and the
# SECOND KEYSIZE worth of bytes, and find the edit distance between
# them. Normalize this result by dividing by KEYSIZE.
#
# d. The KEYSIZE with the smallest normalized edit distance is probably
# the key. You could proceed perhaps with the smallest 2-3 KEYSIZE
# values. Or take 4 KEYSIZE blocks instead of 2 and average the
# distances.
#
# e. Now that you probably know the KEYSIZE: break the ciphertext into
# blocks of KEYSIZE length.
#
# f. Now transpose the blocks: make a block that is the first byte of
# every block, and a block that is the second byte of every block, and
# so on.
#
# g. Solve each block as if it was single-character XOR. You already
# have code to do this.
#
# e. For each block, the single-byte XOR key that produces the best
# looking histogram is the repeating-key XOR key byte for that
# block. Put them together and you have the key.
from prob2 import hex_xor
from prob1 import base64toHex, base64toRaw, rawToHexLUT, rawToHex, hexToRaw
from prob3 import tryKey;
from prob5 import repeating_hex_xor
hexBitCount = { '0':0, '1': 1, '2': 1, '3':2, '4': 1, '5': 2, '6': 2, '7':3, '8': 1, '9': 2,
'a': 2, 'b': 3, 'c': 2, 'd': 3, 'e': 3, 'f': 4,
'A': 2, 'B': 3, 'C': 2, 'D': 3, 'E': 3, 'F': 4};
def hammingDistance(hex1, hex2):
diff = hex_xor(hex1, hex2);
#print(diff);
result = 0;
for c in diff:
result += hexBitCount[chr(c)];
return result;
def findKeySize(hexCipher, numblocks):
bestKeySizes = [0,0,0];
bestScores = [10000000.0,10000000.0,10000000.0];
worstBestIndex = 0; # "best" score to be replaced next"
for i in range(2,41):
str1 = hexCipher[0:2*numblocks*i];
str2 = hexCipher[2*numblocks*i:4*numblocks*i];
diff = hammingDistance(str1, str2);
score = (diff / float(numblocks * i));
if (score < bestScores[worstBestIndex]):
bestKeySizes[worstBestIndex] = i;
bestScores[worstBestIndex] = score;
worstBestIndex = 0;
if (bestScores[1] > bestScores[0]):
worstBestIndex = 1;
if (bestScores[2] > bestScores[worstBestIndex]):
worstBestIndex = 2;
return bestKeySizes, bestScores;
def splitCipher(rawCipher, numBlocks):
splits = []
for i in range(numBlocks):
splits.append(rawCipher[i::numBlocks]);
return splits;
def findKey(split):
bestMg = 0.0;
bestKey = 0;
for i in range(256):
mg, plain = tryKey(rawToHex(split), rawToHexLUT[i]);
if (mg > bestMg):
bestMg = mg;
bestKey = i;
return chr(bestKey);
b64cipher = "HUIfTQsPAh9PE048GmllH0kcDk4TAQsHThsBFkU2AB4BSWQgVB0dQzNTTmVS" + \
"BgBHVBwNRU0HBAxTEjwMHghJGgkRTxRMIRpHKwAFHUdZEQQJAGQmB1MANxYG" + \
"DBoXQR0BUlQwXwAgEwoFR08SSAhFTmU+Fgk4RQYFCBpGB08fWXh+amI2DB0P" + \
"QQ1IBlUaGwAdQnQEHgFJGgkRAlJ6f0kASDoAGhNJGk9FSA8dDVMEOgFSGQEL" + \
"QRMGAEwxX1NiFQYHCQdUCxdBFBZJeTM1CxsBBQ9GB08dTnhOSCdSBAcMRVhI" + \
"CEEATyBUCHQLHRlJAgAOFlwAUjBpZR9JAgJUAAELB04CEFMBJhAVTQIHAh9P" + \
"G054MGk2UgoBCVQGBwlTTgIQUwg7EAYFSQ8PEE87ADpfRyscSWQzT1QCEFMa" + \
"TwUWEXQMBk0PAg4DQ1JMPU4ALwtJDQhOFw0VVB1PDhxFXigLTRkBEgcKVVN4" + \
"Tk9iBgELR1MdDAAAFwoFHww6Ql5NLgFBIg4cSTRWQWI1Bk9HKn47CE8BGwFT" + \
"QjcEBx4MThUcDgYHKxpUKhdJGQZZVCFFVwcDBVMHMUV4LAcKQR0JUlk3TwAm" + \
"HQdJEwATARNFTg5JFwQ5C15NHQYEGk94dzBDADsdHE4UVBUaDE5JTwgHRTkA" + \
"Umc6AUETCgYAN1xGYlUKDxJTEUgsAA0ABwcXOwlSGQELQQcbE0c9GioWGgwc" + \
"AgcHSAtPTgsAABY9C1VNCAINGxgXRHgwaWUfSQcJABkRRU8ZAUkDDTUWF01j" + \
"OgkRTxVJKlZJJwFJHQYADUgRSAsWSR8KIgBSAAxOABoLUlQwW1RiGxpOCEtU" + \
"YiROCk8gUwY1C1IJCAACEU8QRSxORTBSHQYGTlQJC1lOBAAXRTpCUh0FDxhU" + \
"ZXhzLFtHJ1JbTkoNVDEAQU4bARZFOwsXTRAPRlQYE042WwAuGxoaAk5UHAoA" + \
"ZCYdVBZ0ChQLSQMYVAcXQTwaUy1SBQsTAAAAAAAMCggHRSQJExRJGgkGAAdH" + \
"MBoqER1JJ0dDFQZFRhsBAlMMIEUHHUkPDxBPH0EzXwArBkkdCFUaDEVHAQAN" + \
"U29lSEBAWk44G09fDXhxTi0RAk4ITlQbCk0LTx4cCjBFeCsGHEETAB1EeFZV" + \
"IRlFTi4AGAEORU4CEFMXPBwfCBpOAAAdHUMxVVUxUmM9ElARGgZBAg4PAQQz" + \
"DB4EGhoIFwoKUDFbTCsWBg0OTwEbRSonSARTBDpFFwsPCwIATxNOPBpUKhMd" + \
"Th5PAUgGQQBPCxYRdG87TQoPD1QbE0s9GkFiFAUXR0cdGgkADwENUwg1DhdN" + \
"AQsTVBgXVHYaKkg7TgNHTB0DAAA9DgQACjpFX0BJPQAZHB1OeE5PYjYMAg5M" + \
"FQBFKjoHDAEAcxZSAwZOBREBC0k2HQxiKwYbR0MVBkVUHBZJBwp0DRMDDk5r" + \
"NhoGACFVVWUeBU4MRREYRVQcFgAdQnQRHU0OCxVUAgsAK05ZLhdJZChWERpF" + \
"QQALSRwTMRdeTRkcABcbG0M9Gk0jGQwdR1ARGgNFDRtJeSchEVIDBhpBHQlS" + \
"WTdPBzAXSQ9HTBsJA0UcQUl5bw0KB0oFAkETCgYANlVXKhcbC0sAGgdFUAIO" + \
"ChZJdAsdTR0HDBFDUk43GkcrAAUdRyonBwpOTkJEUyo8RR8USSkOEENSSDdX" + \
"RSAdDRdLAA0HEAAeHQYRBDYJC00MDxVUZSFQOV1IJwYdB0dXHRwNAA9PGgMK" + \
"OwtTTSoBDBFPHU54W04mUhoPHgAdHEQAZGU/OjV6RSQMBwcNGA5SaTtfADsX" + \
"GUJHWREYSQAnSARTBjsIGwNOTgkVHRYANFNLJ1IIThVIHQYKAGQmBwcKLAwR" + \
"DB0HDxNPAU94Q083UhoaBkcTDRcAAgYCFkU1RQUEBwFBfjwdAChPTikBSR0T" + \
"TwRIEVIXBgcURTULFk0OBxMYTwFUN0oAIQAQBwkHVGIzQQAGBR8EdCwRCEkH" + \
"ElQcF0w0U05lUggAAwANBxAAHgoGAwkxRRMfDE4DARYbTn8aKmUxCBsURVQf" + \
"DVlOGwEWRTIXFwwCHUEVHRcAMlVDKRsHSUdMHQMAAC0dCAkcdCIeGAxOazkA" + \
"BEk2HQAjHA1OAFIbBxNJAEhJBxctDBwKSRoOVBwbTj8aQS4dBwlHKjUECQAa" + \
"BxscEDMNUhkBC0ETBxdULFUAJQAGARFJGk9FVAYGGlMNMRcXTRoBDxNPeG43" + \
"TQA7HRxJFUVUCQhBFAoNUwctRQYFDE43PT9SUDdJUydcSWRtcwANFVAHAU5T" + \
"FjtFGgwbCkEYBhlFeFsABRcbAwZOVCYEWgdPYyARNRcGAQwKQRYWUlQwXwAg" + \
"ExoLFAAcARFUBwFOUwImCgcDDU5rIAcXUj0dU2IcBk4TUh0YFUkASEkcC3QI" + \
"GwMMQkE9SB8AMk9TNlIOCxNUHQZCAAoAHh1FXjYCDBsFABkOBkk7FgALVQRO" + \
"D0EaDwxOSU8dGgI8EVIBAAUEVA5SRjlUQTYbCk5teRsdRVQcDhkDADBFHwhJ" + \
"AQ8XClJBNl4AC1IdBghVEwARABoHCAdFXjwdGEkDCBMHBgAwW1YnUgAaRyon" + \
"B0VTGgoZUwE7EhxNCAAFVAMXTjwaTSdSEAESUlQNBFJOZU5LXHQMHE0EF0EA" + \
"Bh9FeRp5LQdFTkAZREgMU04CEFMcMQQAQ0lkay0ABwcqXwA1FwgFAk4dBkIA" + \
"CA4aB0l0PD1MSQ8PEE87ADtbTmIGDAILAB0cRSo3ABwBRTYKFhROHUETCgZU" + \
"MVQHYhoGGksABwdJAB0ASTpFNwQcTRoDBBgDUkksGioRHUkKCE5THEVCC08E" + \
"EgF0BBwJSQoOGkgGADpfADETDU5tBzcJEFMLTx0bAHQJCx8ADRJUDRdMN1RH" + \
"YgYGTi5jMURFeQEaSRAEOkURDAUCQRkKUmQ5XgBIKwYbQFIRSBVJGgwBGgtz" + \
"RRNNDwcVWE8BT3hJVCcCSQwGQx9IBE4KTwwdASEXF01jIgQATwZIPRpXKwYK" + \
"BkdEGwsRTxxDSToGMUlSCQZOFRwKUkQ5VEMnUh0BR0MBGgAAZDwGUwY7CBdN" + \
"HB5BFwMdUz0aQSwWSQoITlMcRUILTxoCEDUXF01jNw4BTwVBNlRBYhAIGhNM" + \
"EUgIRU5CRFMkOhwGBAQLTVQOHFkvUkUwF0lkbXkbHUVUBgAcFA0gRQYFCBpB" + \
"PU8FQSsaVycTAkJHYhsRSQAXABxUFzFFFggICkEDHR1OPxoqER1JDQhNEUgK" + \
"TkJPDAUAJhwQAg0XQRUBFgArU04lUh0GDlNUGwpOCU9jeTY1HFJARE4xGA4L" + \
"ACxSQTZSDxsJSw1ICFUdBgpTNjUcXk0OAUEDBxtUPRpCLQtFTgBPVB8NSRoK" + \
"SREKLUUVAklkERgOCwAsUkE2Ug8bCUsNSAhVHQYKUyI7RQUFABoEVA0dWXQa" + \
"Ry1SHgYOVBFIB08XQ0kUCnRvPgwQTgUbGBwAOVREYhAGAQBJEUgETgpPGR8E" + \
"LUUGBQgaQRIaHEshGk03AQANR1QdBAkAFwAcUwE9AFxNY2QxGA4LACxSQTZS" + \
"DxsJSw1ICFUdBgpTJjsIF00GAE1ULB1NPRpPLF5JAgJUVAUAAAYKCAFFXjUe" + \
"DBBOFRwOBgA+T04pC0kDElMdC0VXBgYdFkU2CgtNEAEUVBwTWXhTVG5SGg8e" + \
"AB0cRSo+AwgKRSANExlJCBQaBAsANU9TKxFJL0dMHRwRTAtPBRwQMAAATQcB" + \
"FlRlIkw5QwA2GggaR0YBBg5ZTgIcAAw3SVIaAQcVEU8QTyEaYy0fDE4ITlhI" + \
"Jk8DCkkcC3hFMQIEC0EbAVIqCFZBO1IdBgZUVA4QTgUWSR4QJwwRTWM=";
if __name__ == "__main__":
bestKeySizes, bestScores = findKeySize(base64toHex(b64cipher), 20);
# print(bestKeySizes);
# print(bestScores);
# after running this with a bunch of different number of blocks, 29 always pops out.
# I'm confident 29 is the right answer.
splits = splitCipher(base64toRaw(b64cipher), 29);
key = "";
for s in splits:
key += (findKey(s));
print("Key: " + str(key));
print("Plain: " + str(hexToRaw(repeating_hex_xor(base64toHex(b64cipher), rawToHex(key)))));