package tryingsomething;

import java.util.Scanner;

/**

* Created by rmukherj on 8/8/16.

* Given an arry A of N integers, print each element in reverse order as a single line of

* space separated integers.

*/

public class ArraysPractice {

public static void main(String[] args){

/*

The below function is take the number of inouts into an array as per console.readline

and then print reverse.

*/

Scanner s = new Scanner(System.in);

int size = s.nextInt();

s.nextLine();

int a[] = new int[size];

for(int i=0;i<size;i++){

a[i]= s.nextInt();

}

for(int i=size-1;i>0;i--){

System.out.println(a[i]+" ");

}

System.out.println(a[0]);

/*

2D Array

1 1 1 0 0 0

0 1 0 0 0 0

1 1 1 0 0 0

0 9 2 -4 -4 0

0 0 0 -2 0 0

0 0 -1 -2 -4 0

*/

int arr[][] = new int[6][6];

Scanner sin = new Scanner(System.in);

int max = -10000;

for (int i=0;i<6;i++)

{

for(int j =0 ;j<6;j++)

{

arr[i][j] = sin.nextInt();

}

}

for (int i=0;i<4;i++)

{

for(int j =0 ;j<4;j++)

{

int output = sum(arr,i,j);

max = max > output ? max: output ;

}

}

System.out.println(max);

}

public static int sum(int[][] a,int i,int j)

{

int sum;

sum = a[i][j] +

a[i][j+1] +

a[i][j+2] +

a[i+1][j+1] +

a[i+2][j] +

a[i+2][j+1] +

a[i+2][j+2];

return sum;

}

}